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16.2 Iterated Integrals

 

Recall that it is usually difficult to evaluate single integrals directly from the definition of an integral, but the Fundamental Theorem of Calculus provides a much easier method. The evaluation of double integrals from first principles is even more difficult, but in this section we see how to express a double integral as an iterated integral, which can then be evaluated by calculating two single integrals.

 

Suppose that $f$ is a function of two variables that is continuous on the rectangle MATH. We use the notation MATH to mean that x is held fixed and $f(x,y)$ is integrated with respect to y from $y=c$ to $y=d.$ Hence we integrate y while treating x as a constant, this is called partial integration with respect to y.


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Now we integrate the function A with respect to x from $x=a$ to $x=b$, we get:


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Above, the integral on the right is called an iterated integral. Usually the brackets are omitted. Thus:


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In a similar manner:


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These iterated integrals mean that we first integrate with respect to one variable (while holding the other fixed) and then integrating with respect to the other variable while holding the first one fixed.

The following theorem gives a practical method for evaluating a double integral by expressing it as an iterated integral (in either order):

 

Fubini's Theorem

If $f$ is a continuous on the rectangle MATH then


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More generally, this is true if we assume that $f$ is bounded on $R$, $f$ is discontinuous only on a finite number of smooth curves, and the iterated integral exist.

 

In the special case where $f(x,y)=g(x)h(y)$ and MATH Then Fubini's Theorem gives


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In the inner integral $y$ is a constant, so $h(y)$ is a constant and we can write


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since $\int_{a}^{b}g(x)dx$ is a constant.

 

Therefore, in this case, the double integral of $f$ can be written as the product of two single integrals:


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