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For single integrals, the region over which we integrate is always an
interval. But for double integrals, we want to be able to integrate a function

not just over rectangles but also over regions D of more general shape. We
suppose that D is a bounded region, which means that D can be enclosed in a
rectangular region R. Then we define a new function F with domain R by:
Picture of D and D within R. See page 1015
If the double integral of F exists over R, the we
define the double integral of

over D by

The definition above makes sense because R is a rectangle and so

F
has been previously defined in section 16.1. The procedure that we have used
is reasonable because the values of

are 0 when

lies outside D. and so they contribute nothing to the integral. This means
that it doesn't matter what rectangle R we use, as long as it contains D. This
is show below:
Picture of region R, with D highlighted and with F above it. If possible, highlight the volume of the graph of F.
A plane region D is said to be of type I if it lies between the graphs of two continuous functions of x, that is,
Where

and

are continuous on

Some examples of type I regions are show below:
Pictures of type one regions
In order to evaluate these integrals, we simply choose the bounds described by D. Therefore to set up an double integral of a type I general region:

Now we simply integrate.
A region of type II is described as follows:
Some examples of type II regions are shown below:
pictures of type 2 regions
Set up a type II double integral as follows:

From the previous sections we already know the following properties:



If

A new property is given below. This property is similar to the property of
single integrals given by the equation

If

where

and

don't overlap except perhaps on their boundaries:
picture of what is described above
Then:

The above property can be used to evaluate double integrals over regions D that are neither type I or type II but can be expressed as a union of regions of type I and type II.
The next property of integrals says that if we integrate the constant
functions

over a region D, we get the area of D:

Finally we can combine some of the previous properties to give the following property:
If

for all

in in D, then

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