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In one dimensional calculus we often use a change of variable (a substitution)
to simplify an integral. By reversing the role of

and

,
we can write the Substitution Rule as
where

and

Another way of writing formula 1 is as follows:
A change of variables can also be useful in double integrals, We have already
seen one example of this: conversion to polar coordinates. The new variables r
and

are related to the old variables x and y by the equations
and the change of variables formula can be written as

where S is the region in the
r
-plane
that corresponds to the region R in the xy-plane.
More generally we consider a change of variables that is given by a
transformation T from the
uv
plane
to the xy-plane:
where x and y are related to u and v by the equations
or, as we sometimes write,
We usually assume that T is a

transformation, which means that g and h have continuous first order partial
derivates. A transformation T is really just a function whose domain and range
are both subsets of

If

then the point

is called the image of the point

If no two points have the same image, T is called one-to-one. The figure below
shows the effect of a transformation T on a region S in the uv-plane. T
transforms S into a region T in the xy-plane called the image of S, consisting
of the images of all points in S.
picture of figure 1 on 1061.
If T is a one-to-one transformation, then it has an inverse transformation

from the xy-plane to the
uv
plane
and it may be possible to solve. the following equations for x and y.
Now lets see how a change of variables affects a double integral. We start
with a small rectangle S in the uv-plane whose lower left corner is the point
(
)
and whose dimensions are

and

figure three on 1062
The image of S is a region R in the xy-plane, one of whose boundary points is

The vector
is the position vector of the image of the point (u,v). the equation of the
lower side of S is

,
whose image curve is given by the vector function r

The tangent vector at

to this image curve is
Similarly, the tangent vector at

to the image curve of the left side of S (namely

is
We can approximate the image region

by parallelogram determined by the secant vectors
these are shown below:
Figure 4 on 1062
However
and so
Similarly
This means that we can approximate R by a parallelogram determined by the
vectors

and

.
Therefore, we can approximate the area of R by the area of this parallelogram,
which is:
Computing this cross product we get:

The determinant that arises in this calculation is called the Jacobian of the transformation and is given a special notation.
The Jacobian of the transformation T given by

and

is

With this notation we can use the above equation to five an approximation of
the area

of R:
where the Jacobian is evaluated at

Next we divide a region S in the uv-plane into rectangles
S
and call their images on the xy-plane
R
Applying the approximation to each
R
,
we approximate the double integral of

over R as follows:

The figure below can help explain:
figure 6 on pg 1063
where the Jacobian is evaluated at

Notice that this double sum is a Riemann sum for the integral

This argument suggest the following theorem is true:
Suppose that T is a one-to-one
C
transformation whose Jacobian is nonzero and that maps a region S in the
uv-plane onto a region R in the xy-plane. Suppose that

is continuous on R and that R and S are type I or type II pane regions. Then:

There is a similar change of variables formula for the triple integrals. Let T be a transformation that maps a region S in uvw-space onto a region R in xyz-space by means of the equations:
The Jacobian of T is the following

determinate:

Under hypotheses similar to those used in the double integral, we have the following formula for triple integrals

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